1-2 of 2 Answers
Putting two 8 ohm speakers in series will give you 16 ohms. If you use both the A and B output, this will essentially put the two 16 ohm circuits back in parallel, bringing the total load back to the amp back down to 8 ohms (depending on how the internals of the receiver handle the A/B switching). This should be ok, but keep two things in mind. 1, the total power of the amp will be shared across all the speakers (thus a lower overall volume at each). 2, if using the same speakers the volume should be the same at all the speakers. It will get more complicated with mismatched speakers, impedance, etc. Avoid lower impedance speakers (i.e. 4 ohm). There are other solutions to what you want, but what you have in mind should be ok given the above criteria.
Sorry, there was a problem. Please try again later.Two 8 ohm speakers in series presents a 16 ohm load to the amplifier. Two in parallel results in 4 ohms. The output amplifier is designed to produce optimum performance into an 8 ohm load, though it will work fine into 16 ohms. Remember that the output power is distributed between the speakers. There should be little difference in over all performance otherwise. If you like wall-busting power you may have less ability to bust the walls, but otherwise this idea is fine. Avoid putting them in parallel. This amplifier will handle 4 ohms under most conditions, but will dissipate quite a bit of heat at high volume levels. It probably wouldn't actually damage the amplifiers, but why stress them out unnecessarily. The 16 ohm solution is a good one.
Sorry, there was a problem. Please try again later.
